The reaction 210Pb 82 → 210Bi 83 + β- + ν is an example of which process?

Prepare for the Junior Radiation Protection (RP) Fundamentals Exam. Ace your test with comprehensive study aids, including flashcards and multiple-choice questions, complete with helpful hints and explanations. Gear up for your exam success!

Multiple Choice

The reaction 210Pb 82 → 210Bi 83 + β- + ν is an example of which process?

Explanation:
This is beta decay, specifically beta minus decay. In beta minus decay a neutron inside the nucleus converts into a proton, releasing an electron (the beta particle) and an antineutrino. The mass number stays the same while the atomic number increases by one. Here, lead-210 (Z = 82) becomes bismuth-210 (Z = 83) with emission of a beta particle and a neutrino, matching the beta minus process. Other processes would change the mass number differently or involve different particles: alpha decay would reduce the mass and charge more, electron capture would lower the atomic number without emitting a beta particle, and positron emission would decrease the atomic number.

This is beta decay, specifically beta minus decay. In beta minus decay a neutron inside the nucleus converts into a proton, releasing an electron (the beta particle) and an antineutrino. The mass number stays the same while the atomic number increases by one. Here, lead-210 (Z = 82) becomes bismuth-210 (Z = 83) with emission of a beta particle and a neutrino, matching the beta minus process. Other processes would change the mass number differently or involve different particles: alpha decay would reduce the mass and charge more, electron capture would lower the atomic number without emitting a beta particle, and positron emission would decrease the atomic number.

Subscribe

Get the latest from Passetra

You can unsubscribe at any time. Read our privacy policy